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Practical Exercise 7: THE MOON AGAIN

ahe measurement showed that the angular size (average) of the Moon in perigee is θ☽per = 33,5' and in apogee is θ☽per = 33,5' and in apogee is θ☽apo  =  29,9'.ahe radius of the Moon is θ☽per = 33,5' and in apogee it is θ☽apo = 29,9'. and in apogee it is R = 1 737 km, determine the numerical eccentricity of the elliptic orbit and its main half-axis. 

Answer:

The key is to start from the definition of angular size:

  a teda

By modifying the last equation we get: .

ahe actual value of the numerical eccentricity is 0,055. The trajectory is therefore almost circular.

where . We determine the main half-axis based on this relation , i.e. , where . After substitution we get a ≐ 378 000 km. We can check the result by using the second relation (for apogee): , kde . After substitution we get a ≐ 378 000 km. VWe can check the result by using the second relation (for apogee):

, where , where . After substitution we get a ≐ 378 000 km. 

We can check the result by using the second relation (for apogee):

.